Java Program to find the Largest and Smallest of N Integers

FINDING THE LARGEST AND SMALLEST OF N NUMBERS

AIM:  To write a program in Java to read N numbers and find the largest and smallest of them.

 

ALGORITHM:

1. Declare variables n, Max and Min of type int in method main()
2. Declare an array of integer named a with 50 elements for storing n integers
3. Create an object of type DataInputStream and store its reference in din.
4. Get the value of n using methds readLine() of din, parseInt() of Integer wrapper class.
5. Read n  integers using for loop and store them in the array a[] using index i
6. Initialize the variables Min and Max with a[0]  (the first Integer in the array)
7. Do the following n times using a for loop:
1. If a[0] > Max then assign it to Max 
2. If a[0] < Min then assign it to Min 
8. Print the value of Min and Max as the smallest and largest of given n numbers.

PROGRAM:

import java.io.*;

public class MinMax {

    public static void main(String args[]) throws IOException

    {

        int n,Min, Max;

        int a[] = new int[50];

        DataInputStream din = new DataInputStream(System.in);

       

        Min = Max = 0;

        System.out.print("Enter the value of n (# inputs) : ");

        n = Integer.parseInt(din.readLine());

       

        for(int i=0; i<n; i++)

        {

            System.out.print("Enter the Number " + (i+1) + " : ");

            a[i] = Integer.parseInt(din.readLine());

        }

       

        Min = Max = a[0];

        for(int i=1; i<n; i++)

        {

            if (a[i] > Max)

                Max = a[i];

           

            if (a[i] < Min)

                Min = a[i];

        }

       

        System.out.println("The Smallest Number is : " + Min);

        System.out.println("The Largest Number is : " + Max);

    }

}

Sample Run: